What are the two consecutive even integers of 168?

Let the two consecutive even integers be (2x) , (2x+2). i.e -14 , -12.

What is the product of 168?

Factors of 168 : 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, and 168….Factors of 168 in Pairs.

What is the integers of 168?

Therefore, three consecutive integers that add up to 168 are 55, 56, and 57.

What is the product of 2 consecutive even integers?

The product of two consecutive even integers is 14 more than their sum. Find the integers. Hi Terry, Since the smaller of the two integers is even it is divisible by 2 and hence it can be written 2n for some integer n.

How do you find the product of two consecutive even integers is 224?

2 Answers

1. Let the first integer be x. since the second is the consecutive even then, it is x+2.
2. x⋅x+2=224. ⇒x2+2x=224. ⇒x2+2x−224=0.
3. ⇒x2+2x−224=0. ⇒(x+16)(x−14)=0.
4. Therefore, The first positive integer is: x=14. The first positive integer is: x+2=16.
5. The two consecutive positive integers whose product is 224 are 14and16.

What are the consecutive even numbers?

Consecutive Even Numbers: Even numbers are numbers that end with 0, 2, 4, 6 or 8. The examples of consecutive even numbers are: 0, 2, 4, 6, 8, 10, 12..

What are the three integers of 168?

Is 167 an integer number?

167 (one hundred [and] sixty-seven) is the natural number following 166 and preceding 168….167 (number)

What 2 even numbers have a product of 48?

numbers are consecutive and even and their product is +48. is also +48. So the two answers are either -8 and -6 or +6 and +8.

What is the two consecutive even integers whose product is 48?

The product of two consecutive even integers is 48. Since integers are positive. The two integers are 6 and 8. The two integers are 6 and 8.